(2x-1)(x^2-3x+5)=0

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Solution for (2x-1)(x^2-3x+5)=0 equation: 


Simplifying
(2x + -1)(x2 + -3x + 5) = 0

Reorder the terms:
(-1 + 2x)(x2 + -3x + 5) = 0

Reorder the terms:
(-1 + 2x)(5 + -3x + x2) = 0

Multiply (-1 + 2x) * (5 + -3x + x2)
(-1(5 + -3x + x2) + 2x * (5 + -3x + x2)) = 0
((5 * -1 + -3x * -1 + x2 * -1) + 2x * (5 + -3x + x2)) = 0
((-5 + 3x + -1x2) + 2x * (5 + -3x + x2)) = 0
(-5 + 3x + -1x2 + (5 * 2x + -3x * 2x + x2 * 2x)) = 0
(-5 + 3x + -1x2 + (10x + -6x2 + 2x3)) = 0

Reorder the terms:
(-5 + 3x + 10x + -1x2 + -6x2 + 2x3) = 0

Combine like terms: 3x + 10x = 13x
(-5 + 13x + -1x2 + -6x2 + 2x3) = 0

Combine like terms: -1x2 + -6x2 = -7x2
(-5 + 13x + -7x2 + 2x3) = 0

Solving
-5 + 13x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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